>IEEE -0. results from a calculation of subnormal numbers underflowing to -0.=
>0
>
>I don't recall another path (other than bit stuffing) to get an IEEE negativ=
>e zero
complex :: j=cmplx(0.0, -1.0), z=(0.0, -4.0)
write (*,*) j*z
end
This gives:
( -4.00000000 , -0.00000000 )
I don't think there are subnormals or underflow here.
Anton
|