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>IEEE -0. results from a calculation of subnormal numbers underflowing to -0.= >0 > >I don't recall another path (other than bit stuffing) to get an IEEE negativ= >e zero complex :: j=cmplx(0.0, -1.0), z=(0.0, -4.0) write (*,*) j*z end This gives: ( -4.00000000 , -0.00000000 ) I don't think there are subnormals or underflow here. Anton