You can download a free DOS program from my website. Robert Newcombe
has lots of stuff, including Excel spreadsheets, to do a variety of methods:
http://www.cardiff.ac.uk/medicine/epidemiology_statistics/research/statistics/newcombe/proportions
Martin
Vicent Giner Bosch wrote:
> First of all, sorry for posting an 'off topic' and very easy question, but I
> needed it.
>
> If I want to compute a 95% confidence interval (two-tailed) for an unknown
> proportion "p" within a population, I know the equation for it, if the
> sample size "n" is high enough to assume normality -that is:
>
> CI95%(p) = estimated_p +/- z(0.025) * SQRT( estimated_p*(1-estimated_p) /
> n )
>
> isn't it?
>
> But, what if "n" is small (between 10 and 20, say), and we can't or don't
> want to assume normality? I know I should use binomial distribution, but I
> don't know exactly how.
>
> Thank you in advance for your contributions.
>
> Yours,
>
>
> --
> Vicent
>
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--
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J. Martin Bland
Prof. of Health Statistics
Dept. of Health Sciences
Seebohm Rowntree Building Area 2
University of York
Heslington
York YO10 5DD
Email: [log in to unmask]
Phone: 01904 321334
Fax: 01904 321382
Web site: http://martinbland.co.uk/
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Disclaimer: The messages sent to this list are the views of the sender and cannot be assumed to be representative of the range of views held by subscribers to the Radical Statistics Group. To find out more about Radical Statistics and its aims and activities and read current and past issues of our newsletter you are invited to visit our web site www.radstats.org.uk.
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