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CCP4BB  August 2007

CCP4BB August 2007

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Subject:

Re: Questions about diffraction

From:

James Holton <[log in to unmask]>

Reply-To:

James Holton <[log in to unmask]>

Date:

Tue, 28 Aug 2007 08:56:16 -0700

Content-Type:

text/plain

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For a full answer to all your questions, I refer you to the classic 
textbook of M. M. Woolfson "an introduction to x-ray crystallography" by 
Cambridge University Press. This book has been quite helpful to me of 
late.  Unlike some similar texts I find it easy to read.  There are even 
examples!  With real numbers!  Woolfson begins by describing scattering 
as it was originally derived by J. J. Thomson from classical mechanics 
of a charged mass (the electron) vibrating in an electric field (the 
photon), and takes you, step-by-step all the way to Bragg scattering 
from a rotating 3-D crystal.


You have received many comments so far, so I will try not to repeat 
those in answering your questions here:

1) yes, x-ray sources are "non-coherent", but the photons ARE coherent 
on a short length scale.  Specifically, this is about 0.7 micron if the 
x-rays are 1 A in wavelength and have a spectral dispersion of 1/7000, 
such as with a Si(111) monochromator.  That is, after traveling 0.7 
micron, two photons that were once in phase will no longer be, because 
they have different wavelengths.  This is approximately the "coherence 
length" in the direction of propagation.  The other two directions are 
... more complicated.  It is actually quite difficult to make an x-ray 
source with a very short spatial coherence.  I've heard "talk" about 
shaping x-ray wavefronts in next-generation accelerators, such as the 
ERL planned at CHESS.  Thus would have the advantage of changing the 
phase relationship between atoms as you described and (potentially) 
getting phase information directly.  However, I don't think anybody has 
actually done this yet.

2)  In general, photons do not interfere with each other.  Have you ever 
heard of photon-photon scattering?  Neither have I.  However, there 
actually is a body of work on multi-photon correlations in scattering.  
Apparently, two photons can have correlated wave functions, and this 
leads to correlations in the arrival time of photons at the detector: 
something called the Hanbury-Brown and Twiss effect.  The math behind it 
it a bit beyond me.  However, theoretically, such correlated scattering 
events could be used to get phase information if you have a fast 
detector and a REALLY fast source.  My colleague Ken Frankel 
<[log in to unmask]> can tell you more about it if you are interested.

2b) WRT the "all electrons scattering together" question.  Yes, they do 
all scatter "together" because they are all confined in the same atom.  
The total scattering is explained by integrating Thomson's scattering 
formula (including the phase shift) over all of the electron positions.  
Yes, a single photon can interact with more than one electron, just as a 
single photon can pass through two slits in the famous experiment by 
Thomas Young.  For any given photon, the positions of each electron will 
(in the classical view) be at some well-defined position, but we 
experimentally integrate over a LOT of photons. 
    If no two photons ever see a consistent arrangement of electron 
positions (such as when you shoot x-rays at a free electron beam) then 
the scattering is "incoherent" and the scattered intensity distribution 
you see simply follows Thomson's classical scattering formula for one 
electron, with the intensity multiplied by the number of electrons in 
the x-ray beam. 
    However, if the "electron density" is not random but instead has 
some kind of consistent feature from photon to photon, then the 
interference of the scattered waves will also be consistent as it builds 
up on your detector.  This "binding effect" is only significant on the 
length scale of the electron confinement (the size of an atom in this 
case), so it falls off with increasing scattering angle.  Remember, the 
phase of the scattered wave depends on the total path length traversed 
by the incident and scattered photons.  The phase shift between 
scattering at any two points in the sample will always become 
vanishingly small at a small scattering angle because the difference in 
path length from one "side" of the atom to the other "side" becomes 
smaller and smaller at low scattering angle.  For larger scattering 
angles there is a larger phase shift, and the interference becomes more 
destructive.  The quantitative angular dependence of scattering from any 
atom is called the "atomic form factor", and it is tabulated in 
${CLIBD}/atomsf.lib.  The "form factor" is why high-angle spots are 
weaker than low-angle spots, even if all the B-factors are zero.  Atomic 
form factors are derived from scattering measurements on gasses (which 
don't have B-factors), and theoretical electron-distribution 
calculations have been found to be consistent with these observations.
    The upper limit to constructive interference from a single atom is 
if all of the electrons in the atom are scattering in phase.  This will 
always occur at vanishingly small scattering angles (forward 
scattering).  Since there is no phase shift the amplitudes add, and you 
square the amplitude to get intensity.  Experimentally, the forward 
scattering intensity (that is: low-angle scattering extrapolated to zero 
angle) from any particle is equal to Z^2 multiplied by Thomson's formula 
(where Z is the number of electrons in the particle).  This is true for 
everything from He gas to protein molecules in solution (as observed by 
SAXS). 
    The reason why you multiply the intensity by just Z (and not Z^2) 
when the electrons are not confined to atoms is because out-of-phase 
amplitudes add "in quadrature": Ftotal=sqrt(sum(F^2)) and I~Ftotal^2.  
In-phase amplitudes just add: Ftotal=sum(F), and I~Ftotal^2.
    In multi-atom particles (such as proteins) you have two (or more) 
atoms that are constrained to be "near" one another.  By "near" I mean 
separated by a distance corresponding to a scattering angle that will 
clear the beamstop.  In this case, the scattering from one atom can 
interfere with that from the other (just as the scattering from 
electrons within the same atom interfere with each other).  Taking the 
vector sum of the form factors of the two atoms together explains the 
total scattering.  I have personally confirmed this with the scattering 
from N2 gas from the cryo-stream at my beamline!  N2 has 14 electrons 
worth of forward scattering, not 7.  If the distance between the two 
atoms is not infinitely precise, then the Gaussian distribution of 
atom-atom vectors in real space becomes a Gaussian in reciprocal space 
that you multiply by the "perfect" two-atom form factor.  There is some 
debate over who first called this a "B factor", but the name has 
certainly stuck.

3) As Dale pointed out, the energy goes into other reflections.  Don't 
forget F(0,0,0).  That is a REAL reflection, and it is always on the 
Ewald sphere.  If you manage to orient a crystal so that no visible 
Bragg peaks intersect the Ewald sphere, then all the elastically 
scattered photons will go into F(0,0,0).  Incidentally, for visible 
light the interference of F(0,0,0) with the main beam gives rise to the 
"index of refraction" effect.  There is an index of refraction for 
x-rays, but it is much smaller.  These and other effects of conservation 
of energy are accounted for in the "dynamical theory" of diffraction, 
and this is what is used for the so-called "three beam" phasing 
technique.  The interaction of scattering and absorption gives rise to 
anomalous dispersion, and this is also explained by the dynamical theory. 
  Bragg's Law and other familiar equations come to us from the 
"kinematic approximation" to the dynamical theory.  This approximation 
involves ignoring small "violations" to conservation of energy and 
conservation of momentum.  For example, an elastically scattered photon 
has changed direction (momentum) without changing energy (wavelength).  
This approximation does ignore conservation of momentum, but the small 
amount of momentum transferred from the crystal to the photon is 
distributed evenly over all the atoms in the crystal, so the "recoil" 
motion of the crystal is very small (and safe to ignore in 
crystallography).  Other things ignored by the kinematic approximation 
are secondary scattering and depletion of the primary (and diffracted) 
beam intensity as it looses photons to scattering.  For protein 
crystals, the kinematic approximation is very good since there are many 
spots and they are all very weak when compared to the incident beam.  I 
bought a different book (not Woolfson) on the dynamical theory so that I 
could understand all this more quantitatively.  This book has served 
well putting me to sleep every night...

-James Holton
MAD Scientist


Michel Fodje wrote:
> Dear Crystallographers,
> Here are a few paradoxes about diffraction I would like to get some
> answers about:
>
> 1. In every description of Braggs' law I've seen, the in-coming waves
> have to be in phase. Why is that? Given that the sources used for
> diffraction studies are mostly non-coherent.
>
> 2. Trying to derive the diffraction condition for a pair of non-coherent
> waves with a phase difference of 'y' where 0 < y < 2pi, I obtain the
> following diffraction condition
> 	y * (lambda/2pi) = 2d sin (theta)
> 	i.e. the phase difference y = 4pi * sin(theta) * d / lambda
> This seems to imply that diffraction will occur if the incident waves
> are not in phase but the phase difference still satisfies the above
> condition. One may be able to envision a case where for a given distance
> d, the diffracting condition will be met for various angles depending on
> the phase shift of the waves diffracting. Does this make sense? Has
> anyone looked at the significance of this relationship before? Any
> pointers will be welcome.
>
> 3. What happens to the photon energy when waves destructively interfere
> as mentioned in the text books. Doesn't 'destructive interference'
> appear to violate the first and second laws of thermodynamics? Besides,
> since the sources are non-coherent, how come the photon 'waves' don't
> annihilate each other before reaching the sample? If they were coherent,
> would we just end up with a single wave any how? With what will it
> interfere to cause diffraction?
>
> I'm sure some of these may have some really obvious answers I may be
> missing. 
>
> Thanks,
>
> Michel
>   

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