Dear All:
Thank you for all of your supporting of my requery!
Finally, I got the final evident using transformation.
If x~Gamma(a,b) and y=kx then
you have y~Gamma(a,b/k) This does not follow the additive property of
Gamma distribution. It is suprised this is different with Normal
distribution.
Many Thanks
Xin
----- Original Message -----
From: "Daniel Molinari" <[log in to unmask]>
To: <[log in to unmask]>
Sent: Thursday, March 29, 2007 10:33 PM
Subject: Re: Scale of gamma distirbution
> Excuse me but for me it is not so evident... If you use the theorem of
> change of variables, you'll find that if y ~ Gamma(n, lambda), then
> x= my ~ Gamma(n, lambda/m) (n=degrees of freedom, lambda=frequency of
> the
> process)
>
> Cheers,
> DANIEL
>
>
> On 3/28/07, Isaac Dialsingh <[log in to unmask]> wrote:
>>
>> Madan Kundu wrote:
>> > Yes. You are right.
>> >
>> > This is quiet evident from the additive property of Gamma
>> distribution.
>> >
>> > Regards
>> > Madan Gopal Kundu
>> >
>> > Xin <[log in to unmask]> wrote:
>> > Dear All:
>> >
>> > If y~Ga(a,b)
>> >
>> > What's about the (n-1)y~Ga(a, (n-1)b), is this right?
>> >
>> >
>> > Many Thanks
>> >
>> >
>> >
>> > --------------
>> >
>> >
>> > Madan Gopal Kundu
>> > Biostatistician and SAS Programmer
>> > Ranbaxy R&D
>> > Gurgaon, Haryana
>> > India
>> > Web: http://www.freewebs.com/madanstata
>> > mobile: 91-9868788406
>> > e-mail: [log in to unmask]
>> >
>> >
>> >
>> >
>> >
>> >
>> >
>> > Click to join Statisticians_group
>> >
>> > ---------------------------------
>> > Here's a new way to find what you're looking for - Yahoo! Answers
>> >
>> >
>> Yes. You can use moment generating functions to prove this.
>>
>> Isaac
>>
>
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