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COMP-FORTRAN-90  1998

COMP-FORTRAN-90 1998

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Subject:

Re: Advice required for fortran90

From:

Lars Mossberg <[log in to unmask]>

Reply-To:

Lars Mossberg <[log in to unmask]>

Date:

Tue, 20 Oct 1998 09:34:28 +0200

Content-Type:

text/plain

Parts/Attachments:

Parts/Attachments

text/plain (105 lines)

At 17:25 1998-10-19 +0200, you wrote:
>
>I have a list of integers file with the following information. The first
>line has two integres - the total number of lines in the file and the
>total number of integres listed in the file.
>Then comes the list of integers, listed line after line. The number of
>integers per line is not known before hand.
>
>Example
>7 22
>5 3 2
>1 3 4
>5 4 2 1
>2 3 6 7
>1 3 6
>5 4 7
>6 4
> 
>I want to read this file and develop a datastructure in which the numbers
>are read into an array (called total) of exact size and the number of
>integers per line is registered in another array (called line). 
>This is how I started.
>Read the first line and allocate the arrays total and line.
>For the above example, the following is done 
>  allocate(total(22))
>  allocate(line(7))
>
>Reading the rest of the file into total is easy. I have a problem with
>reading data into line. How does one read a list of input of unknown size
>in fortran90?
>
>regards
>Assefaw Hadish 
>  
> 
>
>
>

You could do something like this:

PROGRAM integers
  IMPLICIT NONE

  INTEGER :: n_lines, n_total, i
  INTEGER, ALLOCATABLE, DIMENSION(:) :: per_line, total

  OPEN (UNIT=1, FILE="A.DAT", ACTION="READ")
  READ (1, *) n_lines, n_total
  ALLOCATE (per_line(1:n_lines), total(1:n_total))

  READ (1, *) total ! Read in whole array "total".
  REWIND (UNIT=1)   ! Back to beginning.
  READ (1, '()')    ! Skip first line, already dealt with.

  DO i=1, n_lines
    per_line(i) = n_integers_on (1) ! Count numbers per line.
  END DO

  CLOSE (UNIT=1)

  .
  .   Use "per_line" and "total".
  .

  DEALLOCATE (per_line, total)

CONTAINS

  FUNCTION n_integers_on (unit) RESULT (n)
    INTEGER, INTENT(IN)          :: unit
    INTEGER                      :: n
    !
    ! This function interprets a line as a growing list of integers until
it fails,
    ! and returns the number of successfully interpreted integers as result
"n".
    CHARACTER(LEN=512) :: line
    INTEGER            :: istat, iw, i

    READ (unit, '(A)', IOSTAT=istat) line
    n = 1
    DO
      READ (line, *, IOSTAT=istat) (iw, i=1, n)
      IF (istat==0) THEN
        n = n + 1
      ELSE
        ! "n" is one too many now, so:
        n = n - 1 ! and
        EXIT ! out of loop ----------------------------->
      ENDIF
    END DO
  END FUNCTION n_integers_on 
 END PROGRAM integers


Best wishes

Lars Mossberg




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