>in your other posting, you gave the example (using the notation of the
detwin documentation):
DANOTw(h1) = 52
DANOTw(h2) = 28
and if you use the formulas that you cite below, you get the true values
back:
DANOtrue(h1) = (0.6*52 - 0.4*28)/(1-0.8) = 100
DANOtrue(h2) = (0.6*28 - 0.4*52)/(1-0.8) = -20
So then, what's problematic?
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Nothing--I think you're right, and my intuition was wrong. Thanks for correcting my mis-statement.
What would come of detwinning Dano rather than I+/-? I wonder, like you, whether anything would be gained or lost?
JPK
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