Hi Anderson,
Thank you for your answer. I see.
Then, what if use only two EVs for 3 scanners?
EV1: group1 (1/0)
EV2: group2 (1/0)
EV3: age
EV4: sex (+1/-1)
EV5 EV6
0 0 <-- scanner 1
0 1 <-- scanner 2
1 0 <-- scanner 3
The contrasts are then:
C1: [1 -1 0 0 0 0] <-- group difference (A>B) adjusting age,sex, and even scanner types.
C2: [-1 1 0 0 0 0] <-- group difference (A<B) adjusting age,sex, and even scanner types.
Are these matrix and contrast still correct?
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