Yes, that's right.
At least, for our coordinate conventions, if Xori = (x_ori, y_ori, z_ori, 1) and Xref = (x_ref, y_ref, z_ref, 1)
then Xref = A*Xori and Xori = A.inv*Xref
All the best,
On 18 Apr 2013, at 03:32, xuemei <[log in to unmask]> wrote:
> Dear, Jesper
> Thank you for your reply.
> Assume that (x_ref,y_ref,z_ref) is in the reference image, (x_ori,y_ori,z_ori) is in the initial image, and A is the 4*4 affine matrix derived from ‘flirt’.
> May I understand that A.inv*(x_ref,y_ref,z_ref) is consistent with A*(x_ori,y_ori,z_ori) ?
> Many thanks again.