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CCP4BB  June 2011

CCP4BB June 2011

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Subject:

Re: XDS question

From:

[log in to unmask]

Reply-To:

[log in to unmask]

Date:

Tue, 14 Jun 2011 17:12:58 +0200

Content-Type:

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text/plain (91 lines)

Dear Konstatin,

First I would reiterate what Fred has said: you only know the space
group once the structure has been solved and completely refined.
Especially bad maps and unsuccesful molecular replacements may point to
a wrong space group assignment.

Second, what causes strong and weak reflections? I once worked it out
for a case where only one axis was doubled, but I guess that in your
case it might be similar: for the small unit cell, your crystal may look
like AAAAAAAAA (all layers of A's, unit cell is A). In case of the
doubled unit cell, the crystal will look like ABABABABAB (alternating
layers of A and B's, unit cell AB). If A is identical to B, the
scattering of the A's will cancel the scattering of the B's for the odd
reflections and you have the small unit cell. If the A's are a little
different from the B's, your even reflections will have the sum of the
scattering of A and B, and the odd reflections will have the difference.
So if the odd reflections are weak, this means that the differences
between the A and B layers are small and you could consider to ignore
them for a preliminary structure, keeping in mind that the resulting
electron density will be the sum (superposition) of the densities of the
A and B layers. You might get clashes, since the differences in A and B
layers may be caused by the crystal packing so I would increase the
allowed number of clashes e.g. in Phaser. Once you have the small unit
cell, you could try to figure out how the big unit cell may look like.
Your situation might be different, but I would definitively try it.

Herman

-----Original Message-----
From: CCP4 bulletin board [mailto:[log in to unmask]] On Behalf Of
Marco Lolicato
Sent: Monday, June 13, 2011 5:16 PM
To: [log in to unmask]
Subject: Re: [ccp4bb] XDS question

Thank you to all!

@Frederic
>
> I have a problem with the following sentence:
> "if I collect all spots I get good map, but it is impossible to solve
the structure by molecular replacement" - if you have a good map (I
assume electron density map) then the structure is solved... for me a
good map is a map I can interpret.

You're right, I said "good map" instead of "good output values".


@Konstantin
>
> It is possible to process diffraction spots from both crystals using
> XDS. The procedure is described here (under 'Index and integrate
> multiple-crystal diffraction'):
> http://strucbio.biologie.uni-konstanz.de/xdswiki/index.php/Tips_and_Tr
> icks

I tried but with no success! :(


@Kay and all the others

The following links are the images:

http://www.facebook.com/photo.php?fbid=2127189780277&set=o.1363238963856
79&type=1&theater

http://www.facebook.com/photo.php?fbid=2127189180262&set=o.1363238963856
79&type=1&theater

http://www.facebook.com/photo.php?fbid=2127188820253&set=o.1363238963856
79&type=1&theater




...then a little bit more details...
so, if I process only the strong spots I have those cell parameters:
a=b=96.66 c=112.26 alpha=beta=gamma= 90

f I process all the spots I have those cell parameters:
a=b=216.4 c=112.4 alpha=beta=gamma= 90

In both cases the space group is I422.


Thank you again to all, do you have any other suggestion?


Marco

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