> > >at 50% of max the function is wider than at 60%. I seemed to remember the
> > >factor was sqrt(8 ln(2)), ex-radioastronomers find this hard to forget.
> >
> > depends how you define your Gaussian, seems this code must use:
> >
> > exp(-(x**2)/(sigma**2))
> >
> > so that factor is sqrt(4*ln(2)), not sqrt(8*ln(2)). It initially confused
> > me as well.
>
> OK, if sigma is not the standard deviation, then one needs to
> know the source code to figure out what sigma is.
Probably need to clarify what sigma means in the news because others may
have the same reaction as ourselves, i.e. isn't it the familiar
sqrt(8*ln(2)) factor. Was the Gaussian equation obtained from looking
at the code rather than Tim Naylor's papers?
Malcolm
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