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Subject:

Re: denormalised number??

From:

"Russell, Richard" <[log in to unmask]>

Reply-To:

Fortran 90 List <[log in to unmask]>

Date:

Tue, 10 Jun 2003 16:35:34 -0400

Content-Type:

text/plain

Parts/Attachments:

Parts/Attachments

text/plain (39 lines)

In a 32 or 64-bit real number, the first group of bits are used for sign and exponent, and the rest are for mantissa. For maximum precision, all bits of the mantissa are retained, and the exponent gets juggled to the right scale. If I'm not mistaken, on Intel CPUs the most significant bit of the mantissa of a non-zero value is thus assumed to be a one and thus it doesn't even occupy one of the bit places available for mantissa, thus gaining one more bit of precision "free." On old IBM 360/370 mainframes, the floating point format called for normalizing of the mantissa by left-shifting in multiples of four bits (hexadecimal normalization), and the exponent was not a "power of two" exponent (Intel) but a "power of 16" exponent. But that meant that the left-most hex digit could have up to three leading zero bits, so that, for single precision, real numbers had 21-24 bits of precision.

Now as to your original question, the normalization process. As a number (Intel) gets smaller, the mantissa from the internal 80-bit register gets left-shifted as necessary to just shift out the most-significant bit, while the exponent field gets decremented accordingly to keep the scale of the number. When the magnitude of the number gets so small that the exponent has gone to zero, smaller and smaller number can be represented, but with gradual loss of precision as most-significant bits become zeroes (un-normalized numbers). If the denormalizing process is suppressed, then once the smallest real number is reached at full precision, then the only alternative beyond that is to change the stored number to a true zero.

Hope this helps (and I hope I haven't made any misstatements!).

Dick Russell

-----Original Message-----
From: Harry R Millwater [mailto:[log in to unmask]]
Sent: Tuesday, June 10, 2003 4:05 PM
To: [log in to unmask]
Subject: denormalised number??


One of our compilers has a compiler option that says:

   disables IEEE gradual underflow, producing zero instead of a denormalised
number.

Can someone explain what is a "denormalised number"?  I've never seen that
terminology before.

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