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The double infinitive CI is the best way
to handle NNT when the ARR includes the
zero value.
If clinicians have any difficulty
understanding it, it is because we have
done a good job in teaching them its
interpretation. See the following
example.

The percentages of patients achieving
cure in a RCT comparing drugs A and B
were 41% (76/186) and 33% (66/186) for A
and B respectively. The difference in
response rates was 8% and the 95%
confidence interval of the difference in
response rates was - 2% to 20%. The NNT
of A Vs B in this study was 14 (1/.08).
That is for every 14 patients treated
with A instead of B, one additional
patient would be cured. The 95%
confidence interval of the NNT is 6 to
-44. This interval means that the NNT
may be as low as 6 but may go beyond
infinity and may even favor B. The NNT
favoring B Vs A may be as low as 44 but
may go beyond infinity.

>But this is the rub.  Doug Altman's
article (referred to by Zhang)
> shows how to do this, and shows how it
leads to a doubly infinite CI
> for the NNT when the CI for the ARR
spans 0, i.e. when p>0.05.
>I don't think most clinicians can cope
with this (I'd love to
> have more than anecdotal evidence to
base this on, but I'm scared of
> risking mailbox overflow if I ask for
a straw poll of you guys out
> there).  I'm sure it's easier to give
point and interval estimates
> for the ARR - which will be
asymmetrical or more nearly symmetrical
> anyway - preferably expressed on a
percent scale.  For example, the
> ARR might be +10%, with 95% CI from
-5% to +25%.  The NNT is then 10,
> with CI from -infinity to -20 and from
-4 to +infinity.  I know
> which looks simpler to me.



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