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You could use 2/pi*arctan(X/n) for any n > 1; the larger n, the less steep the function. An even simpler function is x/(x+n) Michael > Date: Thu, 26 Apr 2012 14:28:20 -0400 > From: Dan Abner <[log in to unmask]> > Subject: Transformation from (0,+inf) to (0,1) XXXX > > Hi everyone, > > I have a variable (X) with only a lower bound (0) and need to map it > to the (0,1) interval. Can anyone make suggestions on the best way to > do this? > > I was considering: > > 2/pi*arctan(X) > > but this function is VERY steep and does not utlize most of the (0,1) space. > > Suggestions? > > Thanks! > > Dan You may leave the list at any time by sending the command SIGNOFF allstat to [log in to unmask], leaving the subject line blank.