Thank you Pablo for this solution, but how would I generate "replicates" of the first element in your data-vector (i.e. 2) coming from the posterior predictive distribution?

Dipankar




On Thu, Feb 2, 2012 at 10:16 AM, Dr. Pablo E. Verde <[log in to unmask]> wrote:
 
Hi Dipankar,
 
The answer is not, you cannot sample from the predictive posterior in your way.
 
The easy way to sample from the predictive posterior while you using the zeros trick is
by adding artificial missing data to your data vector.
 
So if your data set is in a list:
 
list(x =c(2,5,6,2,4,7,8))
 
Then do
 
list(x =c(2,5,6,2,4,7,8, NA, , NA, NA, NA, NA))
 
the values of x[8:12] are sampled automatically from the predictive posterior.
 
Hope it helps,
 
Pablo
 
 
----- Original Message -----
From: [log in to unmask]" href="mailto:[log in to unmask]" target="_blank">Dipankar Bandyopadhyay
To: [log in to unmask]" href="mailto:[log in to unmask]" target="_blank">[log in to unmask]
Sent: Tuesday, January 31, 2012 8:35 PM
Subject: [BUGS] generating replicates from zeros trick

Hi,

I am interested in generating replicates from the posterior predictive distribution of a r.v. X, which has been programmed in WinBUGS using the zeros trick. Can someone suggest whether I am doing it correctly? So, zeros.rep[] in the code below are my replicates.


K <- 1000
ll[i] <- ......   ##  Log-likelihood of X
zeros[i] < - 0
zeros[i] ~   dpois(phi[i])  ##  Zeros trick
phi[i]  <- - ll[i] + K
zeros.rep[i] ~ dpois(phi[i])   ##  Replicates of y[i] ? 


Thanks a bunch,
Dipankar


______________________________
Dipankar Bandyopadhyay, PhD

Associate Professor,
Division of Biostatistics, School of Public Health,
University of Minnesota 
Minneapolis, MN 55455 USA




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