Hi Daniel,<br><br>Assuming it is a plane mirror (i.e. non-magnifying) then you can simply add the distance of the eye to the mirror to the distance from the projector/monitor to mirror in your equation. The mirror rotates the &quot;cone&quot; of the stimulus by 90 deg, but does not change the distance.<br>
<br>Best<br>Steve<br><br><div class="gmail_quote">2010/1/2 Daniel Sodan <span dir="ltr">&lt;<a href="mailto:[log in to unmask]"><a href="/cgi-bin/wa-jisc.exe?LOGON=A3%3Dind1001%26L%3DSPM%26E%3Dquoted-printable%26P%3D286378%26B%3D--001485eba62643afb7047c49a397%26T%3Dtext%252Fhtml%3B%2520charset%3DISO-8859-1%26pending%3D" target="_parent" >[log in to unmask]</a></a>&gt;</span><br><blockquote class="gmail_quote" style="border-left: 1px solid rgb(204, 204, 204); margin: 0pt 0pt 0pt 0.8ex; padding-left: 1ex;">
<div dir="ltr">Hi,<br><br>Sorry for non-SPM question, bust I hope someone can help me with my basic optics question.<br>I need to calculate stimulus visual angle in the scanner. How I do it? If I make it as:<br>arctan(stimulus_height / distance_from_mirror_to_monitor) I do not take in consideration the distance from the eyes to the mirror. How should I incorporate it?<br>


<br>Thanks for help,<br>Daniel<br>
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