 |
 |
Thanks for the help. Now I understand the reason. I'll get a copy of your book. Richard On Jan 11, 2006, at 5:16 AM, [log in to unmask] wrote: >> I guess: >> >> integer :: N =size(integral) ! wrong >> >> and >> >> integer :: N >> N=size(integral) ! ok >> >> I thought they mean the same thing. But it seems they mean >> differently. > They can mean the same thing. However, an initialization expression > has > restrictions that a normal expression doesn't have. The rules are > quite > complicated if you're just beginning, but they're set out in > Section 7.4 > of "Fortran 95/2003 Explained". > > Regards, > > Mike Metcalf