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Hi. I have recently upgraded from Compaq Visual Fortran 6.6B to 6.6C, and it's now giving me a new exciting warning which I don't understand. The following program, PROGRAM test_I8p8_prog IMPLICIT NONE PRINT '(I8.8)', 13 END PROGRAM test_I8p8_prog generates this warning, C:\PhD\Fem\f90\test_I8p8_project\test_I8p8_prog.f90(5) : Warning: The field width is too small for the number of fractional digits. [8] PRINT '(I8.8)', 13 -----------^ Further experimentation shows that for an integer format Ia.b, it gives the warning only if b>=a-2. I thought that 'a' was the field width, and that 'b' specifies that the integer should be padded to 'b' digits with zeros. I guessed (never I good thing, I know) that the only restriction would be b<=a for positive numbers, and b<=a-1 for negative numbers where you need an extra digit free in the field for the minus sign. However, I don't know what a fractional digit is, and so don't understand the warning. Would someone be able to shed some light on this for me please? Thanks, Paul -- =============================================== Dr. Paul Suckling School of Mathematics and Statistics The University of Birmingham Edgbaston, Birmingham, B152TT, U.K. +44(0)121 4148129 http://web.mat.bham.ac.uk/P.M.Suckling/ ===============================================