----- Original Message ----- From: "Volker Loose" <[log in to unmask]> To: <[log in to unmask]> Sent: Thursday, November 20, 2003 4:53 PM Subject: selecting one of two solutions of a quadratic equation > Hello Derivers, > > is it possible to select one of two solutions of a > quadratic equation? > Example: With L:=solve(x^2-4x-12=0,x) I get > L=(x=6 v x= - 2). > With sub 1 I get the first element of a vector. I'm > looking for something like that in this context. > > > Meanwhile I found out LHS and RHS does what I > want: LHS(L)=(x=6). With RHS(LHS(SOLVE(x^2 - 4·x - 12 = 0, x))) you get directly the first solution: 6 And with RHS(RHS(SOLVE(x^2 - 4·x - 12 = 0, x))) the second one: -2 Saludos, Ignacio Larrosa Caņestro A Coruņa (Espaņa) [log in to unmask]