Hi Stuart, I have a slightly different take on this... When ever you have one categorical variable (drug/no drug) and one continuous variable (stimulus rating), it's invaluable to draw an ANCOVA graph: X-axis stimulus rating, Y-axis response. Draw two lines, one for drug, one for no drug. In the SPM parameterization, the first columns of the design matrix are the intercept for each line (call them beta1 and beta2); the slope of each line are the next two columns (beta3 and beta4). What I would call the natural parameterization is this: The midpoint between the two intercepts is the grand mean, call it alpha0. The distance from the midpoint to each of the two intercepts is the main effect of drug (alpha1). Draw a dotted line that goes through the y-axis at alpha0 and halfway between the two lines; this is the main effect of the covariate, call it alpha 2. The effect that expresses the difference between the two (solid) lines is the drug by stimulus interaction (alpha3). OK, you can put down your pencil now. The point of this is that you obviously want this contrast: alpha0 alpha1 alpha2 alpha3 [ 0 0 0 1 ] Note that this doesn't involve the intercepts (alpha0 and alpha1) at all. Now I can write down the relationship between the alphas and the betas: alpha0 = 1/2*(beta1 + beta2) alpha1 = 1/2*(beta1 - beta2) alpha2 = 1/2*(beta3 + beta4) alpha3 = 1/2*(beta3 - beta4) You can quickly see that the contrast above implies that you want a contrast that tests Ho: 1/2*(beta3 - beta4) = 0. Or simply beta1 beta2 beta3 beta4 [ 0 0 1 -1 ] Again, the intercepts don't come into play. Also, note that the interpretation of beta1 and beta2 (and alpha0 and alpha1) depend crucially upon whether the covariate was centered. If it was centered, then the intercepts are the response at the average covariate value. If it wasn't centered, then the intercepts are the response at covariate value zero, which may, or may not make any sense. Of course, at the end of the day, it doesn't matter as the inferences for estimable contrasts of the intercepts (t's and F's) are the same no matter what. So this answer wasn't one of your hypothesized ones... does this make sense? -Tom -- Thomas Nichols -------------------- Department of Biostatistics http://www.sph.umich.edu/~nichols University of Michigan [log in to unmask] 1420 Washington Heights -------------------------------------- Ann Arbor, MI 48109-2029