>and that could be used to detwin the DANOs directly:
DANOtrue(h1) = ((1-tf)*DANOTw(h1) -tf*DANOTw(h2)) / (1-2tf)
DANOtrue(h2) = ((1-tf)*DANOTw(h2) -tf*DANOTw(h1)) / (1-2tf)
This would be problematic, since many of the signs of DanoTrue would not be known per the Keller Theorem just posted. This would not be a problem, however, when detwinning I+/I-.
A corollary: the twin fraction at which one reflection from a twin-related pair will flip sign is a function of the ratio (Dano/Danotwinrelated); higher ratios flip at lower twin fractions. All Dano twin-pairs with ratios < -2, for example, will have flipped sign with twin fractions > ~0.33. Working right now on pinning down the right function.
JPK
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