I have re-visited these calculations over the weekend. As far as I can
tell, there is just no way to change background-subtracted spot
intensities with "diffuse" scattering unless the motions are somehow
"synchronized" across different unit cells. Call it "optical" or
"acoustic" or whatever you like.
I have now repeated the previously-posted nearBragg simulations with
10x more atoms, but still 10% of the scattering matter involved in a
two-headed displacement. I have also done a "disordered solvent"
simulation where more than half of the unit cell volume is filled with
completely random atoms. In both cases the result was the same as
before: subtracting the "average-electron-density" diffraction image
from the "average diffraction over many configurations" image is a
smooth and "locally uniform" image with no signs of spot intensities.
This implies that subtracting a smooth "local background" from each spot
will yield the Fourier coefficients of the average electron density (as
long as the crystal has no "synchronized disorder").
Examples of "synchronized disorder" would be something like a sound wave
moving through the crystal. This would cause the motion of atoms in one
unit cell to be related in some way to those in another. Another way to
do this is if the lattice is distorted by defects. As this is a pet
model of mine, I have now added an example of it on my little web page:
http://bl831.als.lbl.gov/~jamesh/diffuse_scatter/index.html#dilatation
This effect does produce little "bumps" under Bragg peaks that can
become quite significant. Perhaps this is the "acoustic DS" that Ian is
talking about? Or perhaps it should be called "defect DS"?
The really interesting bit I think is that no matter what the
lattice-distortion model, the fractional changes in spot intensities are
the same. If this is true in general, then such a "synchronized
disorder correction" would be fairly easy to incorporate into a
refinement program (very few new parameters). The shape of the DS
between spots could guide this correction, but might be unnecessary if
the disorder is apparent in the average electron density. So, I can
still claim to be relevant to the original post!
-James Holton
MAD Scientist
Ian Tickle wrote:
> James, I think the problem is that your simulation just doesn't contain
> enough atoms in the unit cell with correlated displacements to exhibit
> significant optic DS, i.e. with only 1 or 2 atoms it will be dominated
> by Einstein-model DS which as I explained before is locally uniform and
> therefore can be fitted by a planar background function.
>
> Cheers
>
> -- Ian
>
>
>> -----Original Message-----
>> From: [log in to unmask] [mailto:[log in to unmask]]
>>
> On
>
>> Behalf Of James Holton
>> Sent: 29 January 2010 09:43
>> To: [log in to unmask]
>> Subject: Re: [ccp4bb] Refining against images instead of only
>>
> reflections
>
>> All I'm saying is that when I calculate the average general scattering
>> from 8192 random configurations of one disordered atom per unit cell:
>> http://bl831.als.lbl.gov/~jamesh/diffuse_scatter/xtal_diffuse.gif
>> and then subtract from that the general scattering from an
>> "occupancy-weighted model" with the two possible atom positions are at
>> half occupancy:
>> http://bl831.als.lbl.gov/~jamesh/diffuse_scatter/xtalAB_Fsum.gif
>> I get an difference image that shows only the smooth diffuse-scatter
>> background, with no spots to speak of:
>>
>>
> http://bl831.als.lbl.gov/~jamesh/diffuse_scatter/xtals_diffuse_minus_Fsu
> m.
>
>> gif
>>
>> But, if I calculate the average general scattering from an "all A" and
>> an "all B" crystal:
>> http://bl831.als.lbl.gov/~jamesh/diffuse_scatter/xtalAB_Isum.gif
>> and subtract from it the same partial-occupancy model image as above:
>> http://bl831.als.lbl.gov/~jamesh/diffuse_scatter/xtalAB_Fsum.gif
>> I get an image where some of the spots have been subtracted out, but
>> others are still quite pronounced:
>>
>>
> http://bl831.als.lbl.gov/~jamesh/diffuse_scatter/xtals_Isum_minus_Fsum.g
> if
>
>> So, in the first case, the partial-occupancy model produced exactly
>>
> the
>
>> same background-subtracted spot intensities as the "unsynchronized
>> disorder" case, but this was not so when the disorder was
>>
> synchronized.
>
>> What did I do wrong?
>>
>> As far as my "operational" definition of a "Bragg peak" (a term which
>> already has two definitions), I am merely suggesting that the
>> nearly-universal practice of subtracting the "local background" is a
>> very pragmatic definition of a "spot intensity". Nearly all available
>> data were collected in this way, and it actually is a reasonable thing
>> to do if the disorder from cell to cell is uncorrelated (as evidenced
>> above).
>>
>> However, I totally agree with you that the disorder in protein
>>
> crystals
>
>> may well be correlated across large patches of unit cells. If that is
>> the case, then the "average occupancy model" that is all but
>>
> universally
>
>> implemented by refinement programs will never be able to explain the
>> background-subtracted spot intensities.
>>
>> -James Holton
>> MAD Scientist
>>
>>
>> Ian Tickle wrote:
>>
>>>> If all cells are completely unsynchronized, then the
>>>>
>>>>
>>> occupancy-weighted
>>>
>>>
>>>> average electron density map of all the conformers will fully
>>>>
> explain
>
>>>> the background-subtracted spot intensities, but if there is
>>>> cell-to-cell synchronization: it won't!
>>>>
>>>>
>>> This is not correct: as I tried to explain in a previous posting,
>>>
> the
>
>>> 'optic' mode DS component which arises from what I would call 'short
>>>
> to
>
>>> medium range' correlated displacements (that is correlations due to
>>> rigid side-chain motions, or of secondary-structure units,
>>>
> individual
>
>>> helices say, or of whole domains within the same molecule, or of
>>> different molecules within the same unit cell), give rise to a
>>> non-uniform DS distribution over the *whole* diffraction pattern.
>>>
> You
>
>>> can't assume that the contributions of the optic DS at the Bragg
>>> positions are zero just because they can't be measured! From the DS
>>> equation there's absolutely no reason why the DS should be anything
>>> other than non-uniform at the Bragg position as anywhere else.
>>>
> Since
>
>>> it's equally non-uniform over the whole pattern, including at and
>>>
> around
>
>>> the Bragg positions, a planar background correction can't possibly
>>> remove it from the integrated Bragg intensities. So it's simply not
>>> correct to say that the mean electron density explains all the
>>>
> intensity
>
>>> at the Bragg positions. There will be a residual I(diffuse) =
>>> I(coherent) - I(Bragg) which is everywhere positive, as I
>>>
> demonstrated.
>
>>> I agree with you that what I would call 'long-range' correlations
>>> between different unit cells contribute largely to the 'acoustic'
>>>
> mode
>
>>> DS which is centred largely *at* the Bragg peaks. You say 'if' the
>>> cells are completely unsynchronised, but that's a big 'if' -
>>>
> certainly
>
>>> you can't simply assume that it's true.
>>>
>>> On another point you said you wanted an 'operational' definition of
>>> I(Bragg). I'm not entirely clear what you mean by that. Are you
>>>
> saying
>
>>> that you want I(Bragg) to be the total background-subtracted
>>>
> integrated
>
>>> intensity under the peak at the Bragg position, i.e. what I'm
>>>
> calling
>
>>> I(coherent). If so then it can't be the contribution from the mean
>>> density at the same time! - seems to me that's what everyone means
>>>
> by
>
>>> I(Bragg) (including you I thought!) so changing the definition will
>>> cause total confusion!
>>>
>>> Cheers
>>>
>>> -- Ian
>>>
>>>
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