Aha, so I have re-invented the wheel! But I never made sense of why f' is
negative--this is beautiful! Just to make sure: you are saying that the real
part of the anomalous scattering goes negative because those photons are
sneaking out of the diffraction pattern through absorption-->fluorescence?
Jacob
*******************************************
Jacob Pearson Keller
Northwestern University
Medical Scientist Training Program
Dallos Laboratory
F. Searle 1-240
2240 Campus Drive
Evanston IL 60208
lab: 847.491.2438
cel: 773.608.9185
email: [log in to unmask]
*******************************************
----- Original Message -----
From: "Ethan Merritt" <[log in to unmask]>
To: "Jacob Keller" <[log in to unmask]>; <[log in to unmask]>
Sent: Friday, April 24, 2009 1:40 PM
Subject: Re: [ccp4bb] Reason for Neglected X-ray Fluorescence
> On Friday 24 April 2009 11:28:16 Jacob Keller wrote:
>> Dear Dr. Holton and CCP4BBers,
>>
>> Are you saying that a resonant event is always accompanied by a
>> fluorescence
>> event? If that were true, wouldn't the resonant event end up manifesting
>> as
>> *negative* scattering component from the resonant atom, due to the
>> elimination of an otherwise-scattered photon, this making the resonant
>> atom
>> "darker" than would be expected?
>
> Yes.
> That is why the real component of the scattering factor, f', is negative.
>
>
> --
> Ethan A Merritt
> Biomolecular Structure Center
> University of Washington, Seattle 98195-7742
>
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