Knee-jerk answer: The magnitude of the rotation component of the
transformation yielded from the optimal least squared superposition
of the two domains. Implicit is the ability to generate said least
squared superposition.
On Jul 7, 2007, at 8:21 PM, Bernhard Rupp wrote:
> Not that I want to open a can of worms here...
> but could someone explain what is meant
> with 'angle between domains'?
>
> Thx, br
>
> -----Original Message-----
> From: CCP4 bulletin board [mailto:[log in to unmask]] On Behalf
> Of Das,
> Debanu
> Sent: Saturday, July 07, 2007 7:51 PM
> To: [log in to unmask]
> Subject: Re: [ccp4bb] how to convert matrix to angle
>
> Hi,
> You can also use LSQKAB in CCP4 to get the angle between two similar
> domains.
>
> -Debanu.
>
>
> -----Original Message-----
> From: CCP4 bulletin board on behalf of Kay Diederichs
> Sent: Sat 7/7/2007 7:30 AM
> To: [log in to unmask]
> Subject: Re: [ccp4bb] how to convert matrix to angle
>
> Jiamu Du schrieb:
>> Dear all:
>> I want to calculate the rotation angle between two similar
>> domains. By
>> using Coot, I can superposr the two domain and get the rotation
>> matrix.
>> But how to convert this matrix to an angle. Is there any program can
>> calculate this ?
>> Thanks.
>>
> Jiamu Du,
>
> If you have the rotation matrix
> a11 a12 a13
> a21 a22 a23
> a31 a32 a33
>
> then
>
> (a11 + a22 + a33 - 1) / 2
>
> is the cosine of the angle you're looking for.
>
> HTH,
>
> Kay
> --
> Kay Diederichs http://strucbio.biologie.uni-konstanz.de
> email: [log in to unmask] Tel +49 7531 88 4049 Fax 3183
> Fachbereich Biologie, Universität Konstanz, Box M647, D-78457 Konstanz
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