>I think that is pretty much the way to go. However, as it stands it is
>rank defficient: EV1-EV2+EV3=0.
>So you need delete EV3 and getting its paired difference with a
>[-1 1 0 0 0 0 0] contrast:
Thanks very much. Yes, I though so after I sent the message. I didn't think
of at the time, though, that through contrast setup, I can get the other
pair-wise comprison I need.
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