I am trying to see whether the answer I have to this question if flawed:
If X and Y are two independent random variables each with exponential distribution with mean 1. What is the P(Y>X^2).
I got an answer of 1.13 but when I used Maple on the integrals, I got 0.54564.
Basically I boiled down the double integral to integral of e^(-x-x^2) with respect to x from x=infinity (UPPER LIMIT) to x=0 (LOWER LIMIT).
I completed the square and tried to get it in the form of a normal distribution with mean -0.5 and variance 1/2. But, the answer I am getting is over 1.
Where am I going wrong?
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